Steelers running back Rashard Mendenhall was named the AFC Offensive Player of the Week for his performance in Sunday's 17-13 victory against the Jacksonville Jaguars.
It is the second week in a row the a Steelers player has been so honored.
After sitting out the previous game with a hamstring injury, Mendenhall rushed for 146 yards on 23 carries and scored on an 8-yard run against the Jaguars. He also had a 68-yard run to set up a field goal.
Mendenhall's honor follows quarterback Ben Roethlisberger, who was named offensive player of the week after he threw five touchdown passes against the Tennessee Titans.